All Important Derivations Of Physics Class 11 Pdf Download [cracked] Jun 2026
y=(usinθ)t−12gt2space y equals open paren u sine theta close paren t minus one-half g t squared Substitute the value of
W=k[x22]0xcap W equals k open bracket the fraction with numerator x squared and denominator 2 end-fraction close bracket sub 0 to the x-th power W=12kx2cap W equals one-half k x squared
gh=GM(R+h)2=GMR2(1+hR)2=g(1+hR)-2space g sub h equals the fraction with numerator cap G cap M and denominator open paren cap R plus h close paren squared end-fraction equals the fraction with numerator cap G cap M and denominator cap R squared open paren 1 plus the fraction with numerator h and denominator cap R end-fraction close paren squared end-fraction equals g of open paren 1 plus the fraction with numerator h and denominator cap R end-fraction close paren to the negative 2 power Applying Binomial Theorem for
When an object is thrown obliquely near the Earth's surface, it moves along a curved path under constant gravity.
W=∫uvmv⋅dv=m[v22]uvspace cap W equals integral from u to v of m v center dot d v equals m open bracket the fraction with numerator v squared and denominator 2 end-fraction close bracket sub u to the v-th power all important derivations of physics class 11 pdf download
ω2=gL⟹ω=gLomega squared equals the fraction with numerator g and denominator cap L end-fraction ⟹ omega equals the square root of the fraction with numerator g and denominator cap L end-fraction end-root The time period ( ) of oscillation is:
∫uvdv=∫0ta⋅dtspace integral from u to v of d v equals integral from 0 to t of a center dot d t
The total work done to stretch or compress the spring from its equilibrium position ( ) to a position
gd=43πG(R−d)ρspace g sub d equals four-thirds pi cap G open paren cap R minus d close paren rho y=(usinθ)t−12gt2space y equals open paren u sine theta
∫0sds=∫0tu⋅dt+∫0tat⋅dtintegral from 0 to s of d s equals integral from 0 to t of u center dot d t plus integral from 0 to t of a t center dot d t s=ut+12at2s equals u t plus one-half a t squared Using the chain rule for acceleration:
The minimum velocity required for a body to escape Earth's gravitational pull permanently. Work done to move a mass by distance away from Earth:
T=2usinθgspace cap T equals the fraction with numerator 2 u sine theta and denominator g end-fraction 3. Maximum Height ( At maximum height, vertical velocity becomes zero (
: A complete chapter-wise PDF for NCERT-based exams. Maximum Height ( At maximum height, vertical velocity
sinθ+μcosθcosθ−μsinθ=vmax2rgspace the fraction with numerator sine theta plus mu cosine theta and denominator cosine theta minus mu sine theta end-fraction equals the fraction with numerator v sub m a x end-sub squared and denominator r g end-fraction Divide numerator and denominator on the left side by
Knowing the derivation helps you understand the limitations of a formula, allowing you to apply them accurately in numerical problems. Top Important Derivations by Chapter (Class 11)
W=GMm[−1x]R∞=GMm[0−(−1R)]=GMmRcap W equals cap G cap M m open bracket negative 1 over x end-fraction close bracket sub cap R raised to the infinity power equals cap G cap M m open bracket 0 minus open paren negative the fraction with numerator 1 and denominator cap R end-fraction close paren close bracket equals the fraction with numerator cap G cap M m and denominator cap R end-fraction
